(7/10)x^2+(32/10)x+(15/10)=0

Solution for (7/10)x^2+(32/10)x+(15/10)=0 equation:

(7/10)x^2+(32/10)x+(15/10)=0


Domain of the equation: 10)x^2!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 10)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/10)x^2+(+32/10)x+(+15/10)=0

We multiply parentheses

32x^2+(+7/10)x^2+(+15/10)=0

We get rid of parentheses

32x^2+(+7/10)x^2+15/10=0

We calculate fractions


32x^2=0

a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{64}=0$